The sequence foo = bar; bar = foo looks like a failed attempt to swap the values of two variables. This code mistakenly reassigns both
variables, leading to incorrect and unintended behavior. Using std::mem::swap ensures a correct and intended swap.
Code examples
Noncompliant code example
let mut foo = 1;
let mut bar = 2;
foo = bar; // Noncompliant
bar = foo; // Noncompliant
Compliant solution
let mut foo = 1;
let mut bar = 2;
std::mem::swap(&mut foo, &mut bar); // Compliant
