Double.longBitsToDouble converts the bit pattern into its corresponding floating-point representation. The method expects a 64-bit
long argument to interpret the bits as a double value correctly.
When the argument is a smaller data type, the cast to long may lead to a different value than expected due to the interpretation of
the most significant bit, which, in turn, results in Double.longBitsToDouble returning an incorrect value.
Noncompliant code example
int i = 0x80003800;
Double.longBitsToDouble(i); // Noncompliant - NaN
Compliant solution
long i = 0x80003800L;
Double.longBitsToDouble(i); // Compliant - 1.0610049784E-314
